What is the RMS voltage across a 50-ohm dummy load dissipating 1200 watts?
توضیح
Rearranging P = E² / R gives E = √(P × R) = √(1200 × 50) = √(60000) = 245 volts RMS. The 346-volt figure is the peak voltage, not the RMS voltage the question asks for.
Rearranging P = E² / R gives E = √(P × R) = √(1200 × 50) = √(60000) = 245 volts RMS. The 346-volt figure is the peak voltage, not the RMS voltage the question asks for.