To divide the operating frequency of a transmitter signal so it can be used on a lower frequency band
To feed high-impedance antennas from a low-impedance source
To divide power equally between two 50-ohm loads while maintaining 50-ohm input impedance✓Bonne réponse
To divide the frequency of the input to a counter to increase its frequency range
Explication
A Wilkinson divider splits input power equally between two output ports while still presenting 50 ohms at the input, using two quarter-wave sections of about 70.7 ohms plus a resistor bridging the outputs. That bridging resistor isolates the two outputs from each other and dissipates nothing when the loads are balanced.