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Question 293

How is the efficiency of an RF power amplifier determined?

  1. Divide the DC input power by the DC output power
  2. Divide the RF output power by the DC input powerBonne réponse
  3. Multiply the RF input power by the reciprocal of the RF output power
  4. Add the RF input power to the DC output power

Explication

Efficiency is useful output divided by the power supplied, so for an RF power amplifier it is RF output power divided by DC input power. Reversing that ratio would normally produce a value greater than one and cannot represent efficiency.

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Question 293: How is the efficiency of an RF power amplifier determined? · FCC General Class (Element 3) · Questena