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Question 227

What is the PEP produced by 200 volts peak-to-peak across a 50-ohm dummy load?

  1. 1.4 watts
  2. 100 wattsCorrect answer
  3. 353.5 watts
  4. 400 watts

Explanation

For a sine wave into a resistive load, PEP equals the RMS power: 200 V peak-to-peak is 100 V peak, which is 70.7 V RMS, and 70.7² / 50 = 100 watts. Using the peak-to-peak value directly in the power formula is what yields the 400-watt distractor.

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Question 227: What is the PEP produced by 200 volts peak-to-peak across a… · FCC General Class (Element 3) · Questena